x^2+15.25x+58.1=0

Solution for x^2+15.25x+58.1=0 equation:

x^2+15.25x+58.1=0

a = 1; b = 15.25; c = +58.1;
Δ = b2-4ac
Δ = 15.252-4·1·58.1
Δ = 0.16249999999999
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15.25)-\sqrt{0.16249999999999}}{2*1}=\frac{-15.25-\sqrt{0.16249999999999}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15.25)+\sqrt{0.16249999999999}}{2*1}=\frac{-15.25+\sqrt{0.16249999999999}}{2}
$